# homework help 9594

##360 = 2 * 2 * 2 * 3 * 3 * 5 = 2^3 * 3^2 * 5##

If you are at loss, how to start with this kind of a task, you can always start with checking if the number can be divided by ##2##.

(Reminder: all numbers which have an even last digit are dividable by ##2##.)

So,

## 360 = 2 * 180##.

Let’s go further: ##180## is dividable by ##2## again:

##360 = 2 * 180 = 2 * 2 * 90##

You can divide by ##2## once more:

##360 = 2 * 180 = 2 * 2 * 90 = 2 * 2 * 2 * 45##

Now, ##45## has a ##5## as an odd last digit, so it is not dividable by ##2## anymore.
However, as the last digit is a ##5##, it is can be divided by ##5##:

##360 = 2 * 180 = 2 * 2 * 90 = 2 * 2 * 2 * 5 * 9##

Now, the last thing to do is determining that ##9## is dividable by ##3##:

##360 = 2 * 180 = 2 * 2 * 90 = 2 * 2 * 2 * 5 * 3 * 3##

## = 2^3 * 3^2 * 5##

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